Question

If 60% of a substance (AB) dimerises in a solvent
and rest ionises, then its van't Hoff factor is
(1) 2
(2) 1.1
(4) 1.25
(3) 1​

Answer 1

Answer:

The correct option is (3): 1

Explanation:

Formula to calculate Van't Hoff factor using degree dissociation is as follow.

i = ( 1 - α) + α/n

Here

α = 60/100 =  0.6

n = 2 (Dimerisation) = 1.2

i = ( 1.0 - 0.6 ) + 0.6/1.2

i = 0.4 + 0.5 = 0.9 ~ 1

Thus the value of Van't Hoff factore is 1.