Question

If 60% of the students have iphone,30% of the students have blueberry and 15% of the students have both iphone and blueberry.Out of 1920 students,how many students dont have iphone and blueberry??

Anybody help me...I am bit confused about the question ​

Answer 1

SEE BRO TOTAL PERCENTAGE WILL BE - 100%

SO,

PERCENTAGE OF STUDENT NOT HAVING IPHONE AND BLUEBERRY ARE -- 100 -(60+30) =10%

Answer 2

Given :-

60% of students have iphone

30% of students have blueberry

15% of students have both

Total number of students = 1920

To Find :-

The number of students who have none

Solution :-

Firstly let's find out the total number of students who have iphone and blueberry and the number of students who have both.

60% of 1920

$=\: {\dfrac{60}{100}}\: \times\: 1920$

= 1152 students

Left students = 1920 - 1152 = 768

30% of 768

$=\: {\dfrac{30}{100}}\: \times\: 768$

= 230.4 students

Left students = 768 - 230.4 = 537.6

15 % of 537.6

$=\: {\dfrac{15}{100}}\: \times\: 537.6$

= 80.64 students

Total number of students having either iphone or blueberry or both = (1152 + 230.4 + 80.64) students = 1463.04 students.

Therefore, no. of students who have none = (1920 - 1463.04) students = 456.96 students = 457 students.

Required answer = 457 students.