Question

If 600 gm of sugar solution has 30% sugar in it, how much sugar must be added to make the concentration of sugar 40% in the solution?

Answer 1

Let the mass of solution 1 be 600g (s1)
sugar concentration in s1 = 30% (c1)
let mass of the second solution be s2
and sugar concentration in s2 be c2....

Therefore, by applying direct proportion-
$\frac{s1}{c1} \: = \: \frac{s2}{c2} \\ \\ therefore \\ \frac{600}{30} = \frac{s1}{40} \\ now \\ s1 = \frac{600 \times 40}{30} \\ s1 = 20 \times 40 \\ s1 = 800g$
Hence, we get that the mass of the solution having 40% sugar solution is 800g.
Hence, the amount of sugar we'll have to add to the s1 solution is (800g-600g) 200g.

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