Question

if 60g of water at 20 degree celcius mixed with 5 g of steamat 100 degree then find the final composition and its temprature

Answer 1

Answer:

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Heat energy required to melt 60g of ice =60×80=4800Cal.

Heat energy required to raise the temprature of water at 0 degree centigrade to 100 degree centigrade =100×1×60=6000Cal

Total energy required =4800+6000=10800Cal

This energy is given by the steam by getting converted into water.

Amount of steam getting converted into water is 54010800=20g

Thus, finally total 80gm of water will be there and 40gm of steam.