Question

if 62y3 is a multiple of 3, where is y is a single didgit then what should be the minimum and maximum value of y?

Answer 1

Step-by-step explanation:

Given If 62y3 is a multiple of 3, where is y is a single digit then what should be the minimum and maximum value of y?

• We know that a number is divisible by 3, if sum of digits is divisible by 3
• 62y3
• So sum of digits = 6 + 2 + y + 3
•                            = 11 + y
• We need to put different values of y and check number is divisible by 3
• 11 + 0 = 11                           No
• 11 + 1 = 12                           yes
• 11 + 2 = 13                          No
• 11 + 3 = 14                          No
• 11 + 4 = 15                          yes
• 11 + 5 = 16                          No
• 11 + 6 = 17                           No
• 11 + 7 = 18                         yes
• 11 + 8 = 19                          No
• 11 + 9 = 20                         No
• 11 + 10 = 21                     Yes
• 11 + 11 = 22                        No
• Therefore y can be 1,4,7 or 10
• So minimum value is 1 and maximum is 7

Answer 2

Answer:

The minimum value is 1 and maximum is 7

Step-by-step explanation

Given If 62y3 is a multiple of 3, where is y is a single digit then what should be the minimum and maximum value of y?

We know that a number is divisible by 3, if sum of digits is divisible by 3

62y3

So sum of digits = 6 + 2 + y + 3

= 11 + y

We need to put different values of y and check number is divisible by 3

11 + 0 = 11 No

11 + 1 = 12 yes

11 + 2 = 13 No

11 + 3 = 14 No

11 + 4 = 15 yes

11 + 5 = 16 No

11 + 6 = 17 No

11 + 7 = 18 yes

11 + 8 = 19 No

11 + 9 = 20 No

11 + 10 = 21 Yes

11 + 11 = 22 No

Therefore y can be 1,4,7 or 10

So minimum value is 1 and maximum is 7