Question

if 64^2x-5 = 4*8^x-5

Answer 1

Hey dear!

Here is yr answer......


64^2x-5 = 4×8^x-5

(2^6)^2x-5 = 2^2 × (2^3)^x-5)

2^12x-30 = 2^2 × 2^3x-5

2^12x-30 = 2^3x-3

As the bases are equal, then their powers must be equal!

12x-30 = 3x-3

12x-3x = -3+30

9x = 27

x =27/9

x = 3


Hope it hlpz..

Answer 2

Solution:-

given by:-
${64}^{2x} - 5 = 4 \times {8}^{x} - 5 \\ {64}^{2x} - 4 \times {8}^{x} = 0 \\ {64}^{2x} = 4 \times {8}^{x} \\ {4096}^{x} = {2}^{2} \times {8}^{x} \\ {( \frac{4096}{8} )}^{x} = {2}^{2} \\ {512}^{x} = {2}^{2} \\ {2}^{9x} = {2}^{2} \\ 9x = 2 \\( x = \frac{2}{9} )ans$
☆i hope its help☆