Question

If 64 identical liquid drops of radius 2 cm combine to form a large drop, then its radius will be

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Radius of large drop is 8 cm.

Step-by-step explanation:

Given:

Radius of liquid drop (r)= 2 cm.

Volume of 1 liquid drop = (4/3) $\pi r^{3}$

                                      = (4/3) × $\pi 2^{3}$

                                      = 32$\pi$/3 cub.cm.

Volume of 64 liquid drop = 64 × (32$\pi$/3)

                                           = 2048$\pi$/3 cub.cm.

Volume of 64 liquid drops = volume of large drop = 2048$\pi$/3

Let R be the radius of large drop

2048$\pi$/3= (4/3)$\pi R^{3}$

         $R^{3}$= (2048$\pi$ /3) ÷(4$\pi$ /3)

              = 2048/4=512

        R =$\sqrt[3]{512}$

           R=8