Question

If 64 is divided into the ratio of 2,4 and x and smallest part is 32/3.Find x

Answer 1

Please see the attachment

Answer 2

The value of x is 6.

• Given that 64 is divided in the ratio 2:4:x.
• Let the common multiple be k.
• Therefore , the numbers are 2k , 4k and xk.

2k+4k+xk = 64

k = 64/(6+x).

• Given that the smallest number is 32/3.
• Therefore,

2k = $\frac{32}{3}$

2 × $\frac{64}{(6+x)}$ = $\frac{32}{3}$

$\frac{4}{(6+x)}$ = $\frac{1}{3}$

12 = x+6

x = 6

• The value of x is 6.