Question

if 64 is divided into three parts proportinal to 2,4and 6,the smallest part is

Answer 1

I hope it will help you. .......


if 64 is divided into three parts proportinal to 2,4and 6,the smallest part is .......than 6 will be the smallest part.

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Answer 2

Let the constant be x

Given, 64 is to be divided in three parts proportional to 2, 4 and 6

So, let the numbers be 2x, 4x and 6x respectively.

Their sum = 64


According to the question,

2x + 4x + 6x = 64

➾ 12x = 64

➾ x = $\dfrac{64}{12}$

➾ x = $\dfrac{16}{3}$



1st number ➾ 2x

➾ 2 × $\dfrac{16}{3}$

➾ $\dfrac{32}{3}$


2nd number ➾ 4x

➾ 4 × $\dfrac{16}{3}$

➾ $\dfrac{64}{3}$


3rd number ➾ 6x

➾ 6 × $\dfrac{16}{3}$

➾ $\dfrac{96}{3}$





∴ The smallest part is $\dfrac{96}{3}$