Question

if (64)^x=1/(256)^y,then find the value of 3x+4y

Answer 1

${64}^{x} = \frac{1}{ {256}^{y} } \\ \\ {64}^{x} = {256}^{ - y} \\ \\ {(4)}^{3x} = {(4)}^{ - 4y}$

On comparing...

$3x = - 4y \\ \\ 3x + 4y = 0$

Therefore, 3x + 4y = 0