Question

if 64 X square + 1 by 64 x square is equal to 20 then find the value of 8 x minus 1 by 4 x
${64x}^{2} +1 \div 64 {x }^{2} = 20 \\ \\ 8x - 1 \div 4x =$

Answer 1

ans of the equation is 1