Question

If 64power a=1/256power then 3a+4b+1

Answer 1

Answer:      1

Step-by-step explanation:

$64^{a}=(\frac{1}{256})^b\\\\(2^6)^{a}= (\frac{1}{2^8})^b\\\\2^{6a}=2^{-8b}\\\\6a=-8b\\3a=-4b\\3a+4b=0\\3a+4b+1=1$