if 64x^2 + y^2 = 72 and xy = 2 ,find (4x+y/2)^2
Answers
Answered by
2
64x^2+y^2=72(given)
(4x+y/2)^2=16x^2+y^2/4
= 64x^2+y^2÷4
=72÷4
=18
(4x+y/2)^2=16x^2+y^2/4
= 64x^2+y^2÷4
=72÷4
=18
Similar questions