if 64x2+y2=72 and xy=2 find (4x+y/2)²
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Answered by
4
Answer: 26
Step-by-step explanation:
( 4x + y/2 )^2
= 16 x^2 + y^2/4 + 4xy ( xy = 2 )
= 16 x^2 + y^2/4 + 8
= ( 64 x^2 + y^2 )/4 + 8 ( 64 x^2 + y^2 = 72)
= 72/4 + 8
= 18 + 8
= 26
Answered by
1
Answer:
Step-by-step explanation:
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