Math, asked by bablisweta1993, 6 months ago

If 64xsquare - y = ( 8x + 1 /2) (8x - 1/2), then the value of y is.​

Answers

Answered by mohit762161
2

Answer:

y = 1/4

Step-by-step explanation:

64x^2 - y = ( 8x + 1 /2 ) ( 8x - 1/2 )

64x^2 - y = 8x ( 8x - 1/2 ) + 1/2 ( 8x - 1/2 )

64x^2 - y = 64x^2 - 8x/2 + 8x/2 - 1/4

-y = 64x^2 - 64x^2 - 1/4

-y = -1/4

y = 1/4

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