if 64y8 is exactly divisible by 3 , where y is a digit, what is a least value of y
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if 64y8 is exactly divisible by 3, where y is a digit, then the least value of y is 0.
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there is a condtion for the divisibility of 3.....that sum of the last two digits should be divisible by 4...so y+8=3or9....so y=1.... so.....1 is the correct answer......
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