If 653xy is a 5 digit no. exactly divisible by 80,Then find x+y
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653xy is divisible by 80 that means last digit shld be 0 i.e. y=0 now divide 653x by 8 then u get 5x as remainder....therefore x=6 as 56 is divisible by 8
therefore x+y=6
therefore x+y=6
Mehak111111:
Can u clear my series problem?
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can also be written as (653xy/(8)(10))
here we will use the law of divisibility
the above number has to be divisible by 10 and 8 at the same time.
rule of 10------ number should end with 0
(then only it is divisible by 10)
therefore y=0
rule of 8---- if the last three digit of a whole number is divisible by 8, then whole number is divisible by 8.
3xy should be divisible by 8.
3x0 should be divisible by 8.
by trial and error
x=6.
x+y=6
here we will use the law of divisibility
the above number has to be divisible by 10 and 8 at the same time.
rule of 10------ number should end with 0
(then only it is divisible by 10)
therefore y=0
rule of 8---- if the last three digit of a whole number is divisible by 8, then whole number is divisible by 8.
3xy should be divisible by 8.
3x0 should be divisible by 8.
by trial and error
x=6.
x+y=6
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