Question

if 67 be the 3th term of A.P. and 56 be the 9th term of A.p. then what is the 11 term?

Answer 1

I hope that this will help you.

Answer 2

Answer:

Step-by-step explanation:

Given,

3rd term of A.P = 67

⇒a+2 d = 67  → eq 1

and

9th term of A.P = 56

⇒a+8 d = 56 → eq 2

eq 2 - eq 1

⇒6 d=-11

⇒d= -11/6

from eq 1

⇒a+2 × -11/6 = 67

⇒a- 11/3 = 67

⇒a=67+11/3

⇒a=212/3

∴11th term of A.P = a+10 d

                          =212/3 + 10×-11/6

                          =212/3  - -55/3

                          =212 - 55/3

                          =157/3

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