Math, asked by sathetanmayi, 17 hours ago

If 6ab, 12ab, k and 48 are in proportion, then find the value of k. *
24
20
25
18

Answers

Answered by piyushsinghshrinet7
2

Step-by-step explanation:

  \frac{6ab}{12ab}  =  \frac{k}{48}

 \frac{1}{2}  =  \frac{k}{48}

By cross multiplication

48 = 2k

48/2 = k

24 = k. Answer...

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