Question

If 6L of H2 and 5.6L of Cl2 are mixed and exploded what will be the composition of the final mixture

Answer 1

H2 + Cl2 = 2HCl

1  mole of H2 = 22.4L = 2g

1L = 2/22.4 g

6L = (2 x 6)/22.4 = 0.54g

I mole of Cl2 = 22.4L = 71g

1L = 71/22.4 g

5.6L = (71 x 5.6)/22.4 = 17.75g

Therefore, mass of final mixture is 0.54 + 17.75 = 18.29g