Question

if 6tanA=5 then prove (3cosA-2sinA)/(3cosA+2sinA)=2/7​

Answer 1

Step-by-step explanation:

6 tan A = 5

tan A =5/6

p/b = 5/6

h = √{ 5^2+6^2}

=√{25+36}

=√{61}

=7.810

sin A = 5/√(61)

cos A = 6/√ (61)

(3 cos A- 2 sin A) / (3 cos A + 2 sin A)

= [3×(6/√61) - 2×(5/√61)] / [3×(6√61) +2×(5/√61)]

= 2/7