if 6times the 6th term of an A.P is equal to 9times the 9th term Find the 15th term
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Answered by
15
6.(a+5d)=9.(a+8d)
6a+30d=9a+72d
-3a=42d
a=-14d
15th term=a+14d
15th term=-14d+14d
15th term=0
6a+30d=9a+72d
-3a=42d
a=-14d
15th term=a+14d
15th term=-14d+14d
15th term=0
Answered by
5
Given,
6 times the 6th term of an AP = 9 times of its 9th term
To find,
The value of the 15th term.
Solution,
The 15th term of the AP will be 0.
According to the question,
6 times the 6th term of an AP = 9 times of its 9th term
6.a6 = 9.a9
[The formula to find the nth term is a+(n-1)d where a is the first term, n is the number of the term and d is the common difference.]
6[a+(n-1)d] = 9[a+(n-1)d]
6[a+(6-1)d] = 9[a+(9-1)d]
6(a+5d) = 9(a+8d)
6a+30d = 9a+72d
Moving the terms with a on the left-hand side and with d on the right-hand side,
6a-9a = 72d-30d
-3a = 42d
a = -42d/3
a = -14d ---(1)
Now,
a15 = a+(n-1)d
a15 = a+(15-1)d
a15 = a+14d
Putting the value of a from equation 1,
a15 = -14d+14d
a15 = 0
Hence, the 15th term of the AP is 0.
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