Question

If 6x^2 - 3x - 1 is a factor of ax^3 + bx - 1 (where
a, b are integers), then find the value of b.​

Answer 1

Answer:

p(x)=ax³+bx–1

g(x)=6x²–3x–1=0 ( as x is a root )

x=(3±√33)/12

x=(3+√33)/12 or x=(3–√33)/12