Question

if 6x+5y=9,kx+10y=1 has no solution,then the value of k is

Answer 1

Answer:

No solution = a1/a2 = b1/b2 ≠ c1/c2

a1 = 6; b1 = 5; c1= 9

a2 =k; b2 =10; c2=1

Since, a1/a2 = b1/b2 ≠ c1/c2

$\frac{a1}{a2} = \frac{b1}{b2}$

$\frac{6}{k} = \frac{5}{10}$

By doing Cross-multiplication

5k = 6×10

5k = 60

k = 60/5

k = 12