Question

if 6x+5y=9,kx+10y=1 has no solution,then the value of k is

Answer 1

Answer:

The value of k is 12.

Step-by-step explanation:

In this question, we have been asked to find the value of k for the given linear equation which has no solution.

As we know that the condition of lines having no solution is:

$\frac{a1}{a2}$=$\frac{b1}{b2}$≠$\frac{c1}{c2}$

Here, from the first equation:

6x + 5y = 9

$a_{1}$=6 and $b_{1}$=5

and The next equation is kx + 10y = 1

$a_{2}$ = k and $b_{2}$ = 10

∴ $\frac{6}{k}$=$\frac{5}{10}$

⇒5k=60

⇒k=12

Hence the required value of k is 12.

Answer 2

Answer:

the value of k is k=12

Step-by-step explanation:

in this question you have been asked to find the value of k

so your 1st equation is

6x+5y=9

and

the 2nd equation  is  

kx+10y=1

so we can write

$\frac{6}{k}$=$\frac{5}{10}$=$\frac{9}{1}$

or k=12

and k=$\frac{6}{9}$=$\frac{2}{3}$

K value can never be $\frac{2}{3}$

Hence the required value of k is 12