Question

.If 6x = secθ and 6/x = tanθ, Find the value of 9( x2 - 1/x2 ) .

Answer 1

Answer:

Answer:

9(x²-1/x²)=1/4

Given:

The equations are,

6x=sec∅,

6/x=tan∅

To find:

9(x²-1/x²)=?

Solution:

As we know that,

Sec²A-tan²A=1

The equations are,

6x=sec∅, 6/x=tan∅

Squaring on both sides,

36x²=sec²∅, 36/x²=tan²∅

Now, equation 1-2

We get,

36x²-36/x²=sec²∅-tan²∅

36(x²-1/x²)=1

x²-1/x²=1/36

Multiply by '9' on both sides,

9(x²-1/x²)=9/36=1/4

So, 9(x²-1/x²)=1/4

Step-by-step explanation:

Hope it helps you........