If 6x²y, 12xy², z are in continued proportion then find the value of z.
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Answer:
24y³
Step-by-step explanation:
Since 6x²y , 12xy² , and z are in continued proportion then
6x²y : 12xy² :: 12xy² : z
if a : b = b : c i.e. a/b = b/c i.e. b² = ac
if a , b , c are in continuous proportion then the middle term b is called the mean proportion between 'a' and 'c' , 'a' is the first proportion and 'c' is the third proportion
Thus , if b is the mean proportion between 'a' and 'c'
then b² = ac i.e. b = √(ac)
⇒ (12xy²)² = 6x²y × z
z = (12xy²)² ÷ 6x²y
z = 24y³
Hence the Third term term = 24y³
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