If 6x⁵ +5x³+ x² + 4x-1=a(x-1)⁵ +b(x-1)⁴+ c(x-1)³+d(3-1)² +e(x-1)+f, what is the value of a+2b+3c + 4d +5e+ 6f ? please don't spam this is my homework
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Answer:
sgwgurgeuhuuehh7$737734727_385$862272272528)+73((-(278+4+)+(+)+87
ok
Step-by-step explanation:
53844()28995)(-)5)5??557027637444))6
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