Math, asked by MdAnupMalik5154, 1 year ago

If 6y is a factor of (10!)2 , what is the greatest possible value of y?

Answers

Answered by raghu37
2
Hello Mortals

The answer is 8.

Factors of 6 = 2*3

10! = 10*9*8*7*6*5*4*3*2*1

= 2*5*3*3*2*2*2*7*2*3*5*2*2*3*2*1

= 2^8 * 3^4 * 5^2 * 7


Only two exponents of 2 and 3 are eligible here. Either 2^8 or 3^4.


We have to find greatest possible value of y.
So it'll be 8 ( higer number counts).


AvikRaaj: oesnt means it is wrong
surajmandal738: Chill.. and have a day
AvikRaaj: question is quite correct in its own terms
AvikRaaj: anyway.. hope you understand.. have fun :)
surajmandal738: means you still did not understand why I convey so I feel its futile to carry forward thid argument
raghu37: You'll not see this type of question. Believe me!! Or let time to come, you'll see yourself
surajmandal738: *what
surajmandal738: chill.. Time will tell
AvikRaaj: lol.. its brainly.. it isnt a IITJEE preparation centre or something.. tha you say you wont see this type of question. anyway.. lets end it here.. there are two answers for the people to choose accordingly
surajmandal738: Finally.. a sensible response after a long bout of heated arguments
Answered by AvikRaaj
0

The greatest possible value of a factor is the number itself. That is.. for (10!)2... The greatest factor is (10!)2..

=> 6y=10!*2

=> y=10!*2/6=10!/3


surajmandal738: This is correct
raghu37: you don't know then
surajmandal738: well, keep that to yourself....
raghu37: 6y is factor. understand this. You took as bulk.
surajmandal738: so, you should also know that a number is a factor of itself
raghu37: Here you're mistaken with question. Question is 6^y and (10!)^2. power is there.
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