If 6y is a factor of (10!)2 , what is the greatest possible value of y?
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Answered by
2
Hello Mortals
The answer is 8.
Factors of 6 = 2*3
10! = 10*9*8*7*6*5*4*3*2*1
= 2*5*3*3*2*2*2*7*2*3*5*2*2*3*2*1
= 2^8 * 3^4 * 5^2 * 7
Only two exponents of 2 and 3 are eligible here. Either 2^8 or 3^4.
We have to find greatest possible value of y.
So it'll be 8 ( higer number counts).
The answer is 8.
Factors of 6 = 2*3
10! = 10*9*8*7*6*5*4*3*2*1
= 2*5*3*3*2*2*2*7*2*3*5*2*2*3*2*1
= 2^8 * 3^4 * 5^2 * 7
Only two exponents of 2 and 3 are eligible here. Either 2^8 or 3^4.
We have to find greatest possible value of y.
So it'll be 8 ( higer number counts).
AvikRaaj:
oesnt means it is wrong
Answered by
0
The greatest possible value of a factor is the number itself. That is.. for (10!)2... The greatest factor is (10!)2..
=> 6y=10!*2
=> y=10!*2/6=10!/3
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