Math, asked by sirivallala, 4 hours ago

If 7+4√3 / 7 - 4√3 =X +Y√3 then X = ( )

Answers

Answered by nerd01
0
Solving for 2(−14)2
x
2
(
x

14
)
2
for =7+43√√7−43√√
x
=
7
+
4
3
7

4
3


Like he said, we should rationalize the denominator using the identity (+)(−)=2−2
(
a
+
b
)
(
a

b
)
=
a
2

b
2
This identity is called the difference of squares identity

and the goal of rationalization is to multiply the top and bottom by a number such that it will get rid of the radicals in the denominator - this number is called the conjugate

for example the conjugate of ‾√+√
a
+
b
is ‾√−√
a

b
as multiplying the two together will get rid of the radicals:

(‾√+√)(‾√−√)=−
(
a
+
b
)
(
a

b
)
=
a

b
(from the difference of squares identity)

Let’s apply this to the question :

=7+43√√7−43√√
x
=
7
+
4
3
7

4
3


The conjugate of the denominator 7−43‾√‾‾‾‾‾‾‾‾√
7

4
3
is 7+43‾√‾‾‾‾‾‾‾‾√
7
+
4
3


Multiply the entire expression by the conjugate to get:

7+43√√7−43√√⋅7+43√√7+43√√
7
+
4
3
7

4
3

7
+
4
3
7
+
4
3


=(7+43√)2√(72−(43√)2)√
=
(
7
+
4
3
)
2
(
7
2

(
4
3
)
2
)


=7+43√49−16(3)√
=
7
+
4
3
49

16
(
3
)


=7+43√1√
x
=
7
+
4
3
1


=7+43‾√
x
=
7
+
4
3


also notice that −14=7+43‾√−14=43‾√−7
x

14
=
7
+
4
3

14
=
4
3

7


2(−14)2=((−14))2
x
2
(
x

14
)
2
=
(
x
(
x

14
)
)
2


=((43‾√+7)(43‾√−7))2
=
(
(
4
3
+
7
)
(
4
3

7
)
)
2


Use the difference of squares identity again with =43‾√
a
=
4
3
and =7
b
=
7
to get

((43‾√+7)(43‾√−7))2=(48−49)2
(
(
4
3
+
7
)
(
4
3

7
)
)
2
=
(
48

49
)
2


=(−1)2=1
=
(

1
)
2
=
1


∴2(−14)2=1

x
2
(
x

14
)
2
=
1
Answered by anasansarimohd65
0

Answer:

Let’s apply this to the question :

x=7+43√√7−43√√

The conjugate of the denominator 7−43–√−−−−−−−√ is 7+43–√−−−−−−−√

Multiply the entire expression by the conjugate to get:

7+43√√7−43√√⋅7+43√√7+43√√

=(7+43√)2√(72−(43√)2)√

=7+43√49−16(3)√

x=7+43√1√

x=7+43–√

also notice that x−14=7+43–√−14=43–√−7

x2(x−14)2=(x(x−14))2

=((43–√+7)(43–√−7))2

Use the difference of squares identity again with a=43–√ and b=7 to get

((43–√+7)(43–√−7))2=(48−49)2

=(−1)2=1

∴x2(x−14)2=1

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