Question

If (7/5)^3 × (7/5)^-5 =(7/5)^2x-1,find tha value of x

Answer 1

it is in the form of a^m*a^n=a^(m+n)
then taking only exponential
3-5=2x-1
-3=2x-1
-2=2x
x=-1

Answer 2

hey ....

bases are equal then equate the powers

3-5 = 2x-1
-2 = 2x-1
2x = -2+1
2x = -1
x = -1/2