Question

if (7/8)^3×(7/5)^-5=(7/5)^2x+1 , find the value of x​

Answer 1

Answer:

49/40^3-5=7/5^2x+1

equating the powers:

3-5=2x+1

-2=2x+1

-2-1=2x

-3=2x

x=-3/2

Answer 2

Answer:

x= -3/2

Step-by-step explanation:

(7/8)^3x(7/5)^-5=(7/5)^2x+1

= (49/40)^3-5=(7/5)^2x+1 {m=n}

= 3-5=2x+1

= -2=2x+1

=-2-1=2x

=-3=2x

x=-3/2