if 7,a, 15,b are the consecutive terms of an Ap. then value of a and b will be
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Answer:
a=11 and b=19
Step-by-step explanation:
Given:
•7,a,15,b are in A.P.
From the given sequence of A.P
We conclude that,
first term, a1 = 7
second term, a2 = a
third term, a3 = 15
fourth term, a4 = b
let the common difference be d.
Now,
a3 = a1 + (3-1)*d. {Tn = a+(n-1)*d}
15 = 7 + 2d
then, d = 4
Again,
a2 = a+d
or, a = 7+4
a = 11
similarly,
a4 = a+3d
or, b = 7 +3*4
or, b = 19
Hence , This is the required solution.
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