if 7 grams of N2 and 8 grams of O2 and 22 grams of Co2 are present in a gaseous mixture find mole fraction of N2 in the mixture
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Mole fraction=na/na+nb+nc
where na is no of moles of nitrogen, nb is no of moles of oxygen and nc is no of moles of CO2.
NO OF MOLES = WEIGHT [GIVEN]/GRAM MOLECULAR WEIGHT
na =7/28 =1/4
nb=8/32=1/4
nc =22/44 =1/2
na+nb+nc=1
So, mole fraction X is 1/4/1
That is 1/4or 0.25
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