Question

if 7 is a zero of the polynomial p(x)=
$p(x) = {x}^{2} - (5k - 18)x - 35$
then find the value of k then find another zero of the polynomial ​

Answer 1

Answer:

k=5

Step-by-step explanation:

p(x)=x^2-(5k-18)x-35

p(7)=7^2-(5k-18)*7-35

    =49-35k+126-35

  =49-35k+91

  =-35k+140

35k=140

k=140/35

k=20/5

k=4

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Answer 2

p(x) = x^2 - (5k - 18)x - 35

p(7) = 0

=> (7)^2 - (5k - 18)7 - 35 = 0

=> 49 - 35k + 126 - 35 = 0

=> 14 + 126 = 35k

=> 140 = 35k

=> k = 4

Sum of zeroes = -b/a

=> 7 + ß = (5k - 18)

=> ß = 20 - 18 - 7

=> ß = -5

Thus, k = 4, and other zero is equal to -5