If 7+k ,22-k, and 5k+5 are in A.P then k is
Answers
Answered by
22
Answer:
- k = 3/2
Explanation:
Given A. P.
⇒ (7 + k), (22 - k), and (5k + 5)
We know that difference between the first two terms will be equal to last two terms.
So,
⇒ (22 - k) - (7 + k) = (5k + 5) - (22 - k)
⇒ 22 - k - 7 - k = 5k + 5 - 22 + k
⇒ 29 - 2k = 6k + 17
⇒ 29 - 17 = 6k + 2k
⇒ 12 = 8k
⇒ 12/8 = k
⇒ 3/2 = k
Hence, the value of ‘k’ is 3/2
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Note :
Difference between every two term in a sequence is always same and thus called common difference.
For example :
An A. P. is 10, 20, 30, 40....
Here common difference is 10
Answered by
84
Given :
- 7 + k , 22 - k and 5k + 5 are in A.P
To find :
- K = ?
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