Question

If 7 sin? 0 + 3 cos2 0 = 4, 0º = 0 < 90°, then find the value of 0.

Answer 1

Answer:

Given,

7sin2θ+3cos2θ=4,00≤θ≤900

3sin2θ+3cos2θ+4sin2θ=4 

3(sin2θ+3cos2θ)+4sin2θ=4

3(1)+4sin2θ=4

4sin2θ=4−3

sin2θ=1/4

Taking square-root on both sides, we get

sinθ=1/2

Thus, θ=300.

Answer 2

Answer:

7sin

2

θ+3cos

2

θ=4,0

0

≤θ≤90

0

3sin

2

θ+3cos

2

θ+4sin

2

θ=4

3(sin

2

θ+3cos

2

θ)+4sin

2

θ=4

3(1)+4sin

2

θ=4

4sin

2

θ=4−3

sin

2

θ=1/4

Taking square-root on both sides, we get

sinθ=1/2

Thus, θ=30

0

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