If 7 sin^2 θ +3 cos 2 θ= 4 , then show that tan θ = 1/√3
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Answer:
Step-by-step explanation:
7sin²θ + 3cos²θ = 4
7sin²θ + 3 cos²θ = 4(sin²θ + cos²θ)
3sin²θ = cos²θ
sin²θ/cos²θ = 1/3
sinθ/cosθ = ± 1 / √3
tanθ = ± 1 / √3
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