Question

if 7 sin 2 bita+ 3 cos square bita = 4 ( sin square bita+ cos square bita ) then show cot bita = under root3

Answer 1

Answer:

cot x = 7±√45

Step-by-step explanation:

7sin2x + 3cos²x = 4(sin²x+cos²x)

14sinxcosx+3cos²x=4

divide by sin x on both sides

14 cotx + 3 cot²x = 4/sin²x

14cot x + 3cot²x = 4cosec²x

cosec²x=cot²x+1

cot²x - 14cotx + 4=0

using quadratic formula

(-b±√b²-4ac)/2a

we get cotx= 7±√45