Question

if 7 sin square theta +3 cos square theta =4 find sec theta+ codex therta

Answer 1

7 sin²A+3cos²A = 4
= 4 sin²A + 3 sin²A + 3 cos²A = 4
 so, 4sin²A +3(1) =4                [∵Sin²A+cos²A =1]
 so, sin²A = 1/4
       So, cos²A = 1-sin²A = 1-1/4 = 3/4
              cosA = √3/2
        and, sinA =1/2

so, Sec A + cosec A = 1/cosA + 1/sinA
                                   = 2/√3 + 2
                                   = 2+2√3/√3

Answer 2

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