if 7 sin square theta + 3 cos square theta is equals to 4 show that tan theta is equal to 1 by route 3
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Amritha007:
Divide both sides with cos2θ
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I tried hard... but it's not coming 1/√3.
U can see the pic...
U can see the pic...
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Hey !!!
7sin²¢ + 3cos²¢ = 4
=>7sin²¢ + 3cos²¢
------------------------- = 4/cos²¢
cos²¢
[dividing by cos²¢ on both side ]
we get .
= 7tan²¢ + 3 = 4sec²¢
=> 7tan²¢ + 3 =4 (1 +tan²¢)•°• sec²¢ = 1 + tan²¢
=> 7sin²¢ + 3 = 4 + 4tan²¢
= >7tan²¢ - 4tan²¢ = 4-3
=> 3tan²¢ = 1/3
=> tan¢ = √1/3
tan¢ = +-1/√3 prooved
~~~~~~~~~~~~~~~~~~~~~~~
Hope it helps you !!!
@Rajukumar111
= >tan²¢ = 1/3
7sin²¢ + 3cos²¢ = 4
=>7sin²¢ + 3cos²¢
------------------------- = 4/cos²¢
cos²¢
[dividing by cos²¢ on both side ]
we get .
= 7tan²¢ + 3 = 4sec²¢
=> 7tan²¢ + 3 =4 (1 +tan²¢)•°• sec²¢ = 1 + tan²¢
=> 7sin²¢ + 3 = 4 + 4tan²¢
= >7tan²¢ - 4tan²¢ = 4-3
=> 3tan²¢ = 1/3
=> tan¢ = √1/3
tan¢ = +-1/√3 prooved
~~~~~~~~~~~~~~~~~~~~~~~
Hope it helps you !!!
@Rajukumar111
= >tan²¢ = 1/3
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