Question

If 7 sin² θ + 3 cos² θ = 4, then sec θ + cosec θ is equal to

Answer 1

Answer:

7sin

2

θ+3cos

2

θ=4

Dividing the equation by cos

2

θ

⇒7

cos

2

θ

sin

2

θ

+3=

cos

2

θ

4

=4sec

2

θ

⇒7tan

2

θ+3=4(1+tan

2

θ)⇒7tan

2

θ+3=4+4tan

2

θ

⇒3tan

2

θ=1⇒tan

2

θ=

3

1

⇒tanθ=

3

1

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