if 7 sin²theta + 3 cos² theta =4 then prove that , cosectheta +sec theta =2+2/√3
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heya☺
my process will be long so don't worry.
7sin^2¢+3cos^2¢=4
7sin^2+3(1-sin^2¢)=4
7sin^2¢+3-3sin^2¢=4
=)4sin^¢=1
=)sin^2¢=1/4
sin¢=1/2=p/h (where p=perpendicular of this right angle and h is height) and b=base
now,b=√h^2-p^2
b=√4-1
b=√3
now,,,cosec¢=h/p=2/1
and sec¢=h/b=2/√3
so,cosec¢+sec¢=2+2/√3 prooved here.
hope it help you
@rajukumar☺11
my process will be long so don't worry.
7sin^2¢+3cos^2¢=4
7sin^2+3(1-sin^2¢)=4
7sin^2¢+3-3sin^2¢=4
=)4sin^¢=1
=)sin^2¢=1/4
sin¢=1/2=p/h (where p=perpendicular of this right angle and h is height) and b=base
now,b=√h^2-p^2
b=√4-1
b=√3
now,,,cosec¢=h/p=2/1
and sec¢=h/b=2/√3
so,cosec¢+sec¢=2+2/√3 prooved here.
hope it help you
@rajukumar☺11
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