If 7 time 7 term of ap is equal to 11 times the 11 term then what will be it's 18 term
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Let the first term be a and the common difference be d.
→ 7 [ a + ( 7-1 )d ] = 11 [ a + ( 11-1 )d ]
→ 7 [ a + 6d ] = 11 [ a + 10d ]
→ 7a + 42d = 11a + 110d
→ 4a = - 68d .
→ 4a + 68d = 0 .
→ 4( a + 17d ) = 0 .
→ a + 17d = 0
→ a + ( 18 - 1 )d = 0
18 th term = 0
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