If 7 time of 7th term of an A.P is
equal to & 11 time
time of its 11th term
then what is the 18th term of this AP
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Answer:
let a = first term and d=common difference.
According to question,
7a7 = 11 a11
=>7(a+6d) = 11(a+10d)
=> 7a-11a = 110d-42d
=> -4a = 68d
=>a = -17d ......(1)
Now , a18 = a +17d
but a = -17 d ..by (1)
so put this value , we get,
a18=-17d +17d =0
hope it helps you
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