If 7 times the 7 ℎ term of an AP is equal to 11 times the 11ℎ term, show that 18ℎ term is zero.
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Answer:
7(a+6d) = 11(a+10d)
7a + 42d = 11a + 110d
4a + 68d = 0
4(a+17d) = 0
18th terms is,
(a+17d) which is 0 from above explanation.
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