If 7 times the 7th term of an A.P. is equal to 11 terms the 11th term , then find it's 14th term
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Answer:
We can see that :
7×T 7=11×T 11
7(a+6d) = 11(a+10d)
7a + 42d = 11a + 110d
7a − 11a = 110d − 42d
−4a = 68d
∴a = −17d
Consider,
T 18 =a+17d
=−17d+17d
= 0
∴T 18 = 0
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