Question

If 7 times the 7th term of an A.P. is equal to 11 times it's 11th term then find its 18th term.​

Answer 1

Answer:

0

Step-by-step explanation:

Let 'a and 'd be the first term and common difference of AP.

Since,

=> 7a7 = 11a11

=> 7[a+(7-1)d]=11[a + (11-1)d]

=> 7a + 42d = 11a + 110d

=> 4a = -68 d

=> a = -68/4

=> a = -17d

Now

=> a18 = a + (18-1)d

=> a18 = - 17d+ 17 x (d)

=> a18 = 0 answer

Answer 2

Answer:

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