If 7 times the 7th term of an A.P. is equal to 11 times it's 11th term then find its 18th term.
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3
Answer:
0
Step-by-step explanation:
Let 'a and 'd be the first term and common difference of AP.
Since,
=> 7a7 = 11a11
=> 7[a+(7-1)d]=11[a + (11-1)d]
=> 7a + 42d = 11a + 110d
=> 4a = -68 d
=> a = -68/4
=> a = -17d
Now
=> a18 = a + (18-1)d
=> a18 = - 17d+ 17 x (d)
=> a18 = 0 answer
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