If 7 times the 7th term of an A.P. is equal to 11 times the 11th term.Find 18th term of A.P.?
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7th term = (a+6d)
11th term = (a+10d)
(a+6d)7 since 7th term of the ap is 7 times and the same for 11th term
(a+6d)7=(A+10d)11 (given)
7a + 42d =11a +110d (on solving)
7a - 11a = 110d - 42d
-4a = -68d
a= -17d
we know 18th term = (a+17d)................................. (i)
now we substitute the value of a in (i)
which emplies,
-17d + 17d
= 0
hence prove..
(a+6d)7 since 7th term of the ap is 7 times and the same for 11th term
(a+6d)7=(A+10d)11 (given)
7a + 42d =11a +110d (on solving)
7a - 11a = 110d - 42d
-4a = -68d
a= -17d
we know 18th term = (a+17d)................................. (i)
now we substitute the value of a in (i)
which emplies,
-17d + 17d
= 0
hence prove..
dinesh204:
thanks very much
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