If 7 times the 7th term of an A.P. is equal to 11times its 11th term, show
that its 18th term is zero.
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Given
7(a+6d)=11(a+10d)
7a+42d=11a+110d
42d-110d=11a-7a
-68d=4a
4a+68d=0
or
a+17d=0 = 18th term
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